When graphing the following equations, which one will be a straight line? a. y = x2 + 2 b. f(x) = x + 1 c. y = |x + 4| d. x2 + y2 = 1  

Aline has a slope of 1/4 and passes through point (0.4,-1/2). what is the value of the y-intercept?

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Abe is a triangle. can you use the sss postulate or the sas postulate to prove triangle abc = triangle aed? by sss only neither apply both apply by sas only