Atrapezoid has vertices at (-6, -3), (-2,5), (2,5) and (6, -3). what is the approximate perimeter of the c trapezoid

If we have two points A(x,y) and B(m,n)
We can calculate the length of AB: AB²=(x-m)²+(y-n)².
Applying this formula we find out the length of 4 sides
A(-6;-3), B(-2;5), C(2;5), and D(6;-3)
A and D are symmetry by Oy and the same to B and C.
And the trapezoid is ABCD
AB²=(-6+2)²+(-3-5)²= 80 and AB=CD=4√5
BC=4, AD=12
the approximate perimeter is AB+BC+CD+AD= 16+4√5= 25