Explain if you can. and don’t say to google it.

Let's first find the equation of the line in the slope-intercept form, y = mx + b.
First, we find the slope.

m = (y2 - y1)/(x2 - x1) = (10 - 2)/(3 - 1) = 8/2 = 4

The slope is 4.

y = mx + b

y = 4x + b

Now we need to find b.

We start with y = 4x + b, and use the point (1, 2) for x and y.

2 = 4(1) + b

2 = 4 + b

b = -2

The equation is

y = 4x - 2

Now we can find the intercepts.
The x-intercept is where the line crosses the x-axis. There, the y-coordinate is 0. We set y = 0, and solve for x.

y = 4x - 2

0 = 4x - 2

-4x = -2

x = 1/2

The x-intercept is (1/2, 0).

The y-intercept is where the line crosses the y-axis. There, the x-coordinate is 0. We set x = 0, and solve for y.

y = 4x - 2

y = 4(0) - 2

y = 0 - 2

y = -2

The y-intercept is (0, -2).

Can you tell us the question