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![f(x)=\frac{5x-1}{x-3}=\frac{5x-15+14}{x-3}=\frac{5x-15}{x-3}+\frac{14}{x-3}=\frac{14}{x-3}+\frac{5(x-3)}{x-3}=\frac{14}{x-3}+5\\\\y=\frac{14}{x}\\\\\Downarrow T_{\vec{a}=[3;\ 5]-translate\ 3\ units\ right\ and\ 5\ units\ up}\\\\f(x)=\frac{14}{x-3}+5](/tpl/images/0205/3982/afa8b.png)
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