How to solve 3x-4y=3 and 5x+2y=5 by addition

To solve for this with addition, or adding the systems straight down to eliminate one variable to solve the other, first multiply the equation 5x+2y=5 by 2 to get 10x+4y=10. Then, add this expression to 3x-4y=3. This would get you to 13x=13 since +4y and -4y cancel out. Then, when you divide both sides by 13 to solve for x, you get x=1. Now that you have x, plug the x value into one of the equations. For this, I'm going to use the equation 3x-4y=3. When you plug the x value into the equation, you get 3(1)-4y=3. This then simplifies to 3-4y=3 and when you get -4y=0, you divide both sides by -4 and you get y=0. As your answer, you get that the values are x=1 and y=0 or (1,0)

It’s hard to understand what you put.. can you show a picture ?