If f(x) = 5x - 1 and g(x) = 2x^2 + 1 , what is the value of ( f x g ) ? a . 254 b . -254 c . 304 d . -304 e . -354

D ( f x g )(-3) =  -304.

Step-by-step explanation:

Given :If f(x) = 5x - 1 and g(x) = 2x² + 1.

To find: what is the value of ( f x g )(-3) .

Solution: We have given that If f(x) = 5x - 1 and g(x) = 2x² + 1.

We need to find ( f x g )(-3) .

f(x) * g(x) = (5x - 1 )*  (2x² + 1).

f(x) * g(x) = 10x³+5x -2x² -1 .

f(x) * g(x) = 10x³-2x² + 5x -1.

( f x g )(-3) = 10 (-3)³ - 2(-3)² +5 (-3) -1.

( f x g )(-3) = 10 ( -27) - 2( 9) - 15 -1

( f x g )(-3) = -270 -18 - 16

( f x g )(-3) =  -304.

Therefore, D ( f x g )(-3) =  -304.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

c

step-by-step explanation: