Identify the triangle that contains an acute angle for which the sine and cosine ratios are equal.

we have to consider a triangle whose acute angle measure is 45° so that the sine and cosine ratios are equal.

Step-by-step explanation:

We need to consider a right angled triangle such that the measure of one of angle is 90° ,the second angle is 45° and hence the third angle could be found by using the fact that the sum of all the angles is 180°.

Hence we get the third angle measure to be 45°

( ∠1+∠2+∠3=180°

90+45+∠3=180

∠3=180-(90+45)

∠3=45° )

so in the right angled triangle if we use our trignometric identity along either angle 2 or angle 3 we get;

sin 45°=

and cos 45°=  

Hence the sine and cosine angle are equal.

So we have to consider a triangle whose acute angle measure is 45° so that the sine and cosine ratios are equal.

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

answer: 819.89 miles across america

step-by-step explanation: