The sum of three consecutive odd numbers is 123. what is the smallest of the three numbers?

Let the smallest of the three odd integer be A. The next integer will be (A+2), and the largest of the three is (A+4) 
Given: A + (A+2) + (A+4) = 123 
Combine like terms and solve for A as follows
3A + 6 = 123Subtract 6 from each side of the equation to yield
3A = 117
Divide both sides by 3. Yields
A = 39 
The sum of three consecutive odd integers is 123. Fd the integers.

1st: 2n+1
2nd: 2n+3
3rd: 2n+5

EQUATION:
2n+1 + 2n+3 + 2n+5 = 6n + 9 = 123
6n = 114
n = 19

1st: 2*19+1 = 39
2nd: 41
3rd: 43

39,41,43 is consecutive. It adds to 123. 39 is the smallest one.

Dis the correct  answer