Theresa has $708 in her account and wishes to throw a party. she plans to include the following: purchase cost ($) decorations 76.92 catering 150.66 musicians 242.15 refreshments 123.36 venue 260.47 when theresa makes the calculations, she finds that she cannot afford everything that she would like to have. what is the cheapest aspect of the party that she can eliminate to keep from overdrawing her account?

To determine the cheapest aspect of the party that Theresa can eliminate to keep from overdrawing her account, you have to add up all costs and then compare the result with the amount of money she has in her account.

$76.92+$150.66+$242.15+$123.36+$260.47=$853.56.

Theresa has $708 in her account and calculates that she needs $853.56, then the difference is

$853.56-$708=$145.56.

Thus, the cheapest aspect of the party that she can eliminate to keep from overdrawing her account is Catering for $150.66. If she eliminates Catering, she will need

$853.56-$150.66=$702.9 < $708

Catering

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation:

the first domain and range set to the left is matched with the top relation, and the second set the set in the middle goes with the bottom relation.