The sum of three consecutive even numbers is 132. what is the smallest of the three numbers ?

It'd be x, then x+2, then x+4 as our integers, equal to 132. We can combine like terms to get 3x+6=132. We can subtract six and get 3x=126. Finally, we can divide both sides by 3, getting us 42 as x- meaning that the integers are 42, 44, and 48. Hope this helps.

X + x+2 + x+4=132

3x = 126

x = 42 the smallest

The 3rd quadrant as 3x+g5ti=56i: 92d-543