12÷3×15(15-6)+3.use order of operations to solve

Step-by-step explanation:

This question its going to be pemdas.

P-parenthesis

E-exponents

M-multiply

D-divide

A-add

S-subtract

that came from left to right.

1. Calculate parenthesis.

(15-6)=9

12/3*15*9+3

2. Multiply and divide from left to right.

12/3*15*9+3

4*15*9

15*4=60

60*9

60*9=540

540+3

3. Finally, add from left to right.

=543

Final 543

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the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: