The hypotenuse of a right triangle is twice the length of one of the legs. the length of the other leg is 192‾‾‾‾√ feet. find the lengths of the leg and hypotenuse.

The solution is:

The following are the given:

h = 2a

b = √192

a^2 + b^2 = h^2

substituting…

a^2 + 192 = (2a)^2

a^2 + 192 = 4a^2

3a^2 = 192

a^2 = 64

= √64

a = 8

so h = 2*8

The answers are:

= 16 ft would be the hypotenuse.

= 8 is the length of the legs.

do you have a picture of the table

no

step-by-step explanation: