Alan sells custom made kites online. he makes a flat profit of $20 per kite, but he pays $20 per day for his website. write an inequality that gives the number of kites alan needs to sell to make at least $900 per week?

52 kites

Step-by-step explanation:

We are given that

Profit of one kite=$20

He pays per day for his website=$20

Number of days in 1 week=7

Allen needs to sell to make atleast in 1 week=$900

We have to write an inequality that gives the number of kites.

Let x be the number of kites.

According to question

adding  140 on both sides

Divide by 20 on both sides

Hence, Allens   need  to sell atleast 52 kites.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)