What is the solution to the following system of equations? 2x + 3y = 6 x + y = 4 the solution of the system of equations is. ( a1 , a2).

I am going to do elimination
2x+3y=6
x+y=4
I multiplied the bottom one by -2
 2x+3y=6
-2x-2y=-8
x cancels out
y=-2
Now to find the x
I am going to use the bottom equation
x+y=4
x+(-2)=4
x-2= 4
 +2=+2
2 crosses out
x=6
So the answer is= (6,-2)
It will be in an ordered pair or coordinate.

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