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the function f(x)=(2/5)x is shown on the coordinate plane.

select from the drop-down menus to correctly describe the end behavior of f(x) .

as x decreases without bound, the graph of f(x) *approaches y = 0* *increases without bound* *decreases without bound*
as x increases without bound, the graph of f(x) *approaches y = 0* *increases without bound* *decreases without bound*

As x decreases without bound, the graph of f(x) increases without bound. As x increases without bound, the graph of f(x) approaches y = 0.

Step-by-step explanation:

The given function is

It is in the form of

Where, a is a constant.

Since the value of a is less than 1, therefore as we increase the power the value of function approaches to y=0 and as we decrease the power the value of function increases.

From the figure it is noticed that as we approached to negative values along the x-axis the graph increases without bound. As we approached to positive values along the x-axis the graph approaches to y=0.

Therefore, we can say that, as x decreases without bound, the graph of f(x) increases without bound and as x increases without bound, the graph of f(x) approaches y = 0.

answer: c is correct, a regular pentagon

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step-by-step explanation:

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