Triangle abc triangle abc is transformed with the center of dilation at the origin. pre-image: △abc with vertices a(−5, −4), b(−7, 3), c(3, −2) image: △ a ′ b ′ c ′ with vertices a ′ (−3.75, −3), b ′ (−5.25, 2.25), c ′ (2.25, −1.5) what is the scale factor of the dilation that maps the pre-image to the image? enter your answer in the box.

3/4

Step-by-step explanation:

even though this is a year late for the real answer its helpful i help so i get same back faster

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: