Mathematics, 30.07.2019 15:30 aaliyahmaile13
Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0 a. 
b. 
c.
d. no solution
Answers: 1
![\bf cos(2\theta)= \begin{cases} cos^2(\theta)-sin^2(\theta)\\ 1-2sin^2(\theta)\\ \boxed{2cos^2(\theta)-1} \end{cases}\\\\ -------------------------------\\\\ cos(2x)-cos(x)=0\implies \boxed{2cos^2(x)-1}-cos(x)=0 \\\\\\ \stackrel{\textit{notice is just a quadratic}}{2cos^2(x)-cos(x)-1=0}\implies [2cos(x)+1][cos(x)-1]=0\\\\ -------------------------------](/tpl/images/0150/9753/06aa7.png)
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Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0 a. [tex] 0, \frac{2 \...
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