Line p passes through the point (5,1) and has a slope of -4/5. what is the equation of line p in standard form? a. 5x +5y=29 b. 4x+5y=29 c. 4x+5y=25 d. 5x+5y=25

Y = mx + b
slope(m) = -4/5
(5,1)...x = 5 and y = 1
now we sub into the formula and find b, the y int
1 = -4/5(5) + b
1 = -4 + b
1 + 4 = b
5 = b
so ur equation is : y = -4/5x + 5...but we need it in standard form..

y = -4/5x + 5add 4/5x to both sides
4/5x + y = 5...now multiply by common denominator 5
4x + 5y = 25 <== standard form

128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3