(show your work plz and explain) the martin's keep goats and chickens on their farm. if there are 23 animals with a total of 74 legs, how many of each type of animal are there? f) 14 chickens, 9 goats g) 19 chickens, 4 goats h) 9 chickens, 14 goats i) 4 chickens, 19 goats

Let g = number of goats
Let c = number of chickens

Now we set up the two equations for the values we know

g + c = 23
4g + 2c = 74 (goats - 4 legs, chickens - 2 legs)

solve for one of the variables in the first equation

g = 23 - c

then substitute this into the second equation

4(23 - c) + 2c = 74

now solve for c

92 - 4c + 2c = 74
92 - 2c = 74
2c = 18
c = 9

now plug this value back into the first equation and solve for g

g + 9 = 23
g = 14

so this means there are 14 goats and 9 chickens (H)