Given that f(x) =3x^2 - 6x + 11 ,find the values of a, b and c for which f(x) = a(x - b)^2 + c

First you have to complete the square. The first step would be 3x^2-6x=-11. Then you divide -6 by 2 and square the number you get. 3x^2-6x+9=-11+9. 3x^2-6x+9=-2. Factor out the three to get 3(x^2-2x+3)=-2. You can't factor what is in the parenthesis. You should then add two to each side. 3(x^2-2x+3)+2.A = 3B= I don't knowC = 2

What are the options

1. 8 or -82. 14 or -143. -11, -3, 0, 7, 10