Amos, peter, and carlos begin running around a circular track the same time, from the same start line. it takes amos 12 minutes to complete the lap around the track. it takes peter 9 minutes, and it takes carlos 8 minutes to complete 1 lap around the track. if the three boys continue running around the track their same rate of speed, in how many mi utes will the three boys pass one another?

Step-by-step explanation:

Givens

Now, to find the time where the pass one another, we just need to find the Greatest Common Factor. Let's use the divisors and multiples of each number.

12: 1, 2, 3, 4, 6, 12, 24, 36, 48, 60, 72.

9: 1, 3, 9, 18, 27, 36, 45, 54, 63, 72.

8: 1, 2, 4, 8, 16, 24, 32, 40, 48, 56, 64, 72

Now, observe that Amos and Peter pass on another after 3 minutes, then again after 36 minutes.

Peter and Carlos pass one another after 72 minutes.

Actually, they all meet at the same time after 72 minutes.

Therefore, the answer is 72 minutes.

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5