⦁find the area of a regular octagon with side lengths 5in. round your answer to the nearest tenth. apparently, this is incomplete so there's more to plz me a=2(1+√2)a^2=2*(1+√2)*5^2=120.71068

Area of octagon = 120.7

Step-by-step explanation:

We know that,

Area of a regular octagon = , where a is the length of the side.

Now, we have a = 5 inches.

Substituting the value of 'a' in the above formula, we have,

Area of a regular octagon =

i.e. Area of a regular octagon =

i.e. Area of a regular octagon =

So, we get the area of the octagon is 120.71068 .

But, it is required to round the answer to the nearest tenth.

Hence, area of the octagon = 120.7 .

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

no one knows lol

step-by-step explanation: