The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0. the equation of this circle in standard form is the center of the circle is at the , and its radius units.

A. (x - 2)^2 + (y + 3)^2 = 18.

B. (2, -3)

C. 3(2^(1/2))

Step-by-step explanation:

The equation of this circle in standard form is (x - 2)^2 + (y + 3)^2 = 18. The center of the circle is at the point (2, -3), and its radius is 3(2^(1/2)) units.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the answer would be c:   ax + b = ax + c

step-by-step explanation: