Find the x-intercepts and y-intercept for the parabola below. write answers as (x, y) coordinates. y=-7x2-4x+3 x-int: y-int:

The equation given is:
y = -7x^2 - 4x + 3

(1) The x intercept occurs at the point that has y = 0, therefore:
y = -7x^2 - 4x + 3
0 = -7x^2 - 4x + 3
(7x-3)(x+1) = 0
either x = 3/7 > the point is (3/7 , 0)
or x = -1 > the point is (-1,0)

(2) The y-intercept occurs at the point that has x = 0, therefore:
y = -7x^2 - 4x + 3
y = -7(0)^2 - 4(0) + 3
y = 3 > the point is (0,3)

The answer to your question is b’(16,14)

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