Arocket is launched at the rate of 11 feet per second from a point on the ground 15 feet from an observer. to 2 decimal places in radians per second, find the rate of change of the angle of elevation when the rocket is 30 feet above the ground.

0.15 rad/s

Step-by-step explanation:

A rocket is launched at the rate of 11 feet per second from a point on the ground 15 feet from an observer.

To find rate of change of angle when the rocket is 30 feet above the ground

Height of rocket, y = 30 feet

Speed of rocket,

Distance of observer from rocket, d = 15 feet

Angle between observer and rocket at height 30 feet is Ф

Distance between observer and rocket launch doesn't change.

So, d=15 will remain constant.

differentiate w.r.t t

Hence, The rate of change of the angle of elevation is 0.15 rad/s

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .