The ages of three friends are consecutively one year apart. together their ages total 48 years. which equation can be used to find the age of each friend (where a represents the age of the youngest friend)? a. 3a=48 b. a(a+1)(a+2)=48 c. a+(a-1)+(a-2)=48 d. a+(a+1)+(a+2)=48

An equation which can be used to find the age of each friend is: D. a + (a+1) + (a+2) =48

Given the following data:

To write an equation which can be used to find the age of each friend:

Since the ages of the three friends are consecutively one year apart, it simply means that the difference between their ages is one (1) respectively and in an ascending order:

For the younger friend (second):

For the young friend (third):

Evaluating as an equation, we have:

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5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2