When multiplied out, the number 2018! = 1 ∙ 2 ∙ 3 ∙∙∙ 2016 ∙ 2017 ∙ 2018 ends in a string of zeros. how many zeros are at the end of this number?

The question can be asked in the following form, which is an equivalent 
form:
How many multiples of 10 that are less than 2018. 
Multiple of 10 are in the form 
If the above number is less than 2018, then we get the equation:
 
We will solve the above inequality like this:
 
We deduce the following:

There are 201 zeros at the end of 2018!.