Consider the recursively defined function below. f(1)=-5.25 f(n)=f(n-1)+1.75, for n=2,3, create the first five terms of the sequence defined by the given function. tiles: [-7.5], [-1.5], [-1.75], [-5.25], [1.75], [-3.5], [0], [1.5] sequence: ?

  -5.25, -3.5, -1.75, 0, 1.75

Step-by-step explanation:

The recursive relation tells you this is an arithmetic sequence with a common difference of 1.75. Each term is 1.75 more than the one before.

To find the 2nd term, add 1.75 to the first term: -5.25 + 1.75 = -3.5

To find the 3rd term, add 1.75 to the second term: -3.5 + 1.75 = -1.75

To find the 4th term, add 1.75 to the third term: -1.75 + 1.75 = 0

and so on ...

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step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)