Me im lost! will give abc has vertices a(0,6) b(4,6) c(1,3). sketch a graph of abc and use it to find the orthocenter of abc. then list the steps you took to find the orthocenter including any necessary points or slopes you had to derive.

The orthocenter is the point where the three altitudes meet.
sketch the graph and you will see that AB is a horizontal line, the altitude is a vertical line through the point (1,3), so the equation of this altitude is x=1

next, find another altitude. I'll use the altitude of BC.
the slope of BC is (6-3)/(4-1)=1, so the slope of the altitude, which is perpendicular to BC going through the point A (0,6), is -1, the equation of the altitude of BC is y=-x+6
the system of equation : x=1
                                       y=-x+6
has a solution (1, 5)
the solution is where the two lines meet, the meeting point is the orthocenter. 

Double check by find the equation for other altitude:
slope of AC: (3-6)/(1-0)=-3
slope of altitude of AC: 1/3
equation of altitude of AC: y=(1/3)x+b
the altitude of AC goes through point B (4,6), so we can find out b by plug x=4, y=6 in the equation: 6=(1/3)*4+b, b=14/3
y=(1/3)x+14/3
Is (1,5) also a solution to this equation? Plug x=1 in the equation, we get y=5, so yes, (1,5) is a point on the third altitude.  
                                        

The correct graph is the second one, with the points being at (-6,0), (2,0) and reaching down to (-2,-8)