On top of a hill, a rocket is launched from a distance 80 ft. above a lake. the rocket will fall into the lake after its engine burns out. the rockets height, h, in ft. above the suface of the lake, is given by the equation h=-16t^2+64t+80, where t is time in seconds. the maximume height of the rocket is ao feet

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

the correct answer option is d. la = πrs.

step-by-step explanation:

we know that for a right cone, the lateral surface area is given by:

lateral area of right cone =

here the value under the square root is equal to slant height so replacing this value by in the formula to get:

lateral area of right cone =

therefore, the correct answer option is d.