The length of a rectangle is 33 meters less than twice the width. if the area of the rectangle is 464464 square meters, find the dimensions.

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Let W be the width in meters
Let L be the length in meters. 

L*W=464464
L=2W-33
(2W-33)*W=464464
2W^2-33W=464464
2W^2-33W-464464=0
Use the quadratic formula to solve for the zeros 
x=-b√b²-4ac/2a
Sub in b=-33 a=2 and c=-464464 and solve using position and negative values for the √b.
We get:
w=490.225 and w=473.725
Through simple algebra we can figure out that x=490.225 is more accurate when using it with the other equations and solving for the given area. 
L=2*490.225-33
L=947.45
947.45*490.225=464463.7

Therefore the length is 947.45m and the width is 490.225m.

Hope this helps!

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