An equilateral triangle with a side length of 6mm and a height of 5.2mm is divided vertically into halves. find the area of one of the halves plz include solution : d

There are two ways you could go about solving this.

You could divide the length of the base (6mm) by 2 and use that to find the area or you could find the area of the whole triangle using 6mm and divide that by 2.

I will use the first method I described:

base = 6/2

base = 3 mm

height = 5.2 mm

area = bh/2

area = (3 * 5.2)/2

area = 7.8 square mm

(don't forget your units)

Using the other method would look like this:

area = bh/2

b = 6

h = 5.2

area = (6 * 5.2)/2

area = 15.6 square mm

area/2 = 7.8 square mm

As you can see either method yields the same result.

Hope this helped.

Cheers and good luck,

Brian

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°