Θlies in quadrant ii . sinθ=47sinθ=47 what is the exact value of cosθ in simplified form?

I am assuming you mean 4/7 as the sine or cosine cannot be higher than 1.

Lets find θ,

θ = [sin-1](4/7) = 34.85 °

But lets take into account that this value is the equivalent in Quadrant I.

If Θ lies in Quadrant II , then θ = 180 ° - 34.85 ° = 145.15 °

So cosθ = cos (145.15) = -0.821

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