Mr. kasberg rides his bike at 6 mph to the bus station. he then rides the bus to work, averaging 30 mph. if he spends 20 minutes less time on the bus than on the bike, and the distace from his house to work is 26 miles, what is the distance from his house to the bus station?

Convert 20 min to hrs: 20/60 = 1/3 hr
Let t = time on the bikethent-(1/3) = time on the bus
Write a dist equation Dist = speed * time:Bike dist + bus dist = 26 mi6t + 30[t-(1/3)] = 26:6t + 30t - 10 = 2636t = 26 + 1036t = 36t = 1 hr on the bike
6 mph for 1 h = 6 mi from house to the bus station
Check solution by finding the distance6(1) + 30(2/3) =6 + 20 = 26 mi