Answer asap: new machine has productivity (measured in the number of produced details) 12% greater than the last model. after replacing the machines during renovation, a plant has 5% fewer new models than it had old models before. by what percent did the number of produced details on this plant change?

6.4%

Step-by-step explanation:

Given:

Productivity of new machine = 12% greater than last model

Number of new machines = -5%

Let's take number of machines = n

Take p as productivity of each machine.

Total productivity = np.

Productivity of new machine will be:

(100% + 12%) * p

= 112%.p

= 1.12p

Number of new machines will be:

(100% - 5%) * n

= 0.95n

From the calculations, total productivity will now be

1.12p * 0.95n

= 1.064np

Percentage Change in total productivity will be:

Converting np to 1 (or any number of your choice), we have:

= 6.4%

Therefore, the percentage change = 6.4%

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.