Provide the first four terms of the following sequence: t1=6 tn=3tn-1+2n

We know that the first term in the sequence is t1=6.

We also know the equation for the n-th term in the sequnce: tn=3tn-1+2n

According this,

the second term is: t2=3t*2-1+2*2=6t-1+4=6t+3

the thirs term is: t3=9t-1+6=9t+5

the fouth term is: t4=12t-1+8=12t+7

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2

step-by-step explanation: