Mathematics, 04.08.2019 08:50 aaliyahlopez85
The initial population of a town is 4100, and it grows with a doubling time of 10 years. what will the population be in 8 years?
Answers: 1
![\bf \textit{Periodic Exponential Growth}\\\\ A=I(1 + r)^{\frac{t}{p}}\qquad \begin{cases} A=\textit{accumulated amount}\\ I=\textit{initial amount}\to &4100\\ r=rate\to 100\%\to \frac{100}{100}\to &1.00\\ t=\textit{elapsed time}\to &8\\ p=period\to &10 \end{cases} \\\\\\ A=4100(1 + 1)^{\frac{8}{10}}\implies A=4100(2)^{\frac{4}{5}}\implies A=4100\sqrt[5]{2^4}](/tpl/images/0168/8479/1cf23.png)
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The initial population of a town is 4100, and it grows with a doubling time of 10 years. what will t...
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