1. an equation is shown below. 2x + y = 3 part a: explain how you will show all of the solutions that satisfy this equation. (4 points) part b: determine three different solutions for this equation. (4 points) part c: write an equation that can be paired with the given equation in order to form a system of equations that is inconsistent.

A) We can first start with the how: our equation is 2x+y=3. First, subtract 2x from each side. We get y=-2x+3. Our Y variable is isolated.
B) Now we can describe which points our equation goes through. One of them is obvious in our form, and that is (0,3) or our y-intercept. Another 2 would be branching off that line, such as (1,1) or (-1,5)
C) To make our system inconsistent, we can easily make another equation, with same slope, but the y-intercept has to be different. Our equation can be y=-2x+2, y=-2x+4, or even y=-2x+3.00000001.

Hope this helps you.

Dwould be the answer

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

ac ≅ ab (given)< cax ≅ < bax   (given)ax ≅ ax (common side)

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

ac ≅ ab (given)< cay ≅ < bay (since < cax ≅ < bax is given and xy is the extension of line ax)ay ≅ ay (common side)

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)