Find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 82. choose the mathematical translation for the given situation. a. 6 x plus 16 equals 82 6x+16=82 b. 6 x plus 8 equals 82 6x+8=82 c. 3 x plus 3 equals 82 3x+3=82 d. 3 x plus 6 equals 82 3x+6=82

Answer is a.  6 x plus 16 equals 82  6x+16=82======if you let  be  the first odd integer, then the three  consecutive odd integers are    because adding two to an odd integer still gets an odd number.for example, 1 + 2 = 371 + 2 = 7353 + 2 = 55all odd, so adding 2 gets the next consecutive odd integer."the first" means  "two times the second" means  you can distribute and it becomes  "three times the third" means  you can distribute and it becomes  if you sum all these expressions up, they should equal 82.   

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!