If f(x)=2x^2+3 and g(x)=x^2-7 find (f+g)(x)

Answer is (f + g)(x) = 3x^2 - 4

Step-by-step explanation:

Given,

f(x) = 2x^2 + 3

g(x) = x^2 - 7

To find : (f + g)(x)

(f + g)(x) = f(x) + g(x)

             = (2x^2 + 3) + (x^2 - 7 )

             = 2x^2 + x^2 + 3 - 7

(f + g)(x) = 3x^2 - 4

Hence we get (f + g)(x) = 3x^2 - 4

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb