Alake near the arctic circle is covered by a thick sheet of ice during the cold winter months. when spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a rate of 0.2 meters per week. after 7 weeks, the sheet is only 2.42 meters thick. let s(t), denote the ice sheet's thickness s (measured in meters) as a function of time t (measured in weeks). write the function's formula. s(t)=

S(t) = 3.82 - 0.2t

Step-by-step explanation:

After 7 weeks, the ice is 2.42 meters thick.  The ice loses 0.2 meters of thickness per week; this means on the 7th week, it has lost 7(0.2) = 1.4 meters of thickness.

This means the ice started at 2.42+1.4 = 3.82 meters thick.

Our function will start at the original thickness of the ice, 3.82 meters.

Since the ice is losing thickness, we will subtract; it loses at a rate of 0.2 meters per week (t), which gives us 0.2t.  This is subtracted from the original, 3.82 meters, giving us

S(t) = 3.82 - 0.2t

susie has 7 apples

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60