Ahorse's heart beats 440 times in 10 minutes. a cow's heart bears 390 times in 6 minutes. which animal has a greater heart rate?

390 ÷ 6 = 65

440 ÷ 10 = 44

The cow has a greater heart rate.

The answer is 41.7 because 1.39 times 30 is 41.7

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.