Which ordered pair is a solution to the system of equations? {2x−y=−12x−4y=8 (7, −5) (1, 3) (8, 2) (−2, −3)

(-2, -3)

Step-by-step explanation:

We assume your system of equations is ...

You can subtract the second equation from the first to get

... (2x -y) -(2x -4y) = (-1) -(8)

... 3y = -9 . . . . . collect terms

... y = -3 . . . . . . divide by 3 . . . . this is sufficient to identify the correct answer

Substituting into the first equation, we have ...

... 2x -(-3) = -1

... 2x = -4 . . . . . add -3

... x = -2 . . . . . . .divide by 2

Now, we're sure the answer is (x, y) = (-2, -3).

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204