** urgent willing to pay high points explain your answer ** what is the least natural number greater than 7 that has a remainder of 7 when divided by 24 and also has a remainder of 7 when divided by 32?

The least natural number is 103(there's probably a better way to do this, but this is what i have.)for dividing by 24: 24 divided by 24 has a remainder of 0.25 divided by 24 has a remainder of 1.26 divided by 24 has a remainder of 2.pattern.therefore, 24+7=31 divided by 24 has a remainder of 7.31 + 24 gets you another number that, when you divide by 24, has a remainder of 7. you're adding on one whole 24.(while 7 divided by 24 has a remainder of 7, the question wants something greater than 7.)list of natural numbers that when divided by 24 has a remainder of 7 (add 24 each time):     31, 55, 79, 103, 127, 32 + 7 = 39 divided by 32 has remainder of 7the next number that when divided by 32 gives back a remainder of 7 is 39+32=71list of natural numbers that when divided by 32 has a remainder of 7 (add 32 each time):     39, 71, 103stop. 103 is the common number of both lists, and it's the first common number.

Iam not sure , but probably 750 or 7.5