1/2*(4+6*3)-9 what is the answer

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

When only separate discreet points are graphed it is called?

Consider the expression below. 9 + 4(x + 2) – 3.1 select the term that best describes "3" in the given expression. o a. coefficient variable exponent constant