Which statement correctly compares 4⋅10−10 and 3⋅[44−3⋅(6+6)]? a.4⋅10−10=3⋅[44−3⋅(6+6)] b.4⋅10−10< 3⋅[44−3⋅(6+6)] or c. 4⋅10−10> 3⋅[44−3⋅(6+6)]

In order to find the answer, we firstly have to solve both expressions:

For the first expression:

4(10)−10 = 40-10=30

For the second expression (taking into account that the order to solve is: the parenthesis first, then the square bracket and finally the braces or curly brackets if there  is any):

3[44−3(6+6)]=3[44−3(12)]= 3[44−36]= 3[8]=24

Comparing the results of both expressions we know the first is greater than the second:

Therefore, the right answer is c:

4(10)−103[44−3(6+6)]

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/

y=1/4x-4

step-by-step explanation: