Jay, kay, and ray found themselves far apart when they stopped for lunch while working in a field. jay could see kay, then turn to his right 59° and see ray. kay could see ray, then turn to her right 63° and see jay. ray could see jay, then turn to his right 58° and see kay. which two were farthest apart? a. ray and jay b. kay and ray c. jay and kay d. kay and ray were the same distance apart as ray and jay.

The longest side of a triangle is opposite the largest angle. So draw the triangle with J, K, and R as it vertices. angle J is 59º, angle K is 63º and angle R is 58º. Side opposite to angle K 63 is the largest side which is JR.

So the longest side is opposite angle K making it side JR.

So Jay and Ray are farthest apart.

Option A is the answer

yes

yes yes yes

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)