14 points, i need an answer
1) part a-find the perimeter of the outside edges of the frame. ( explain and show work)
part b-find the area of the inside of the frame where the picture would belong and the area of the entire frame using the outside values. ( explain and show work)
2) if the area of the frame was 64 inches², what would be 2 possible sets of dimensions that could be used to make a frame with that area? ( explain and show work)
4) the frame is being enlarged to hang on a gallery wall. using the scale factor of 1in=2.5ft., give the new dimensions of the outside edges of the frame. ( explain and show work)

1)

PART-A     Perimeter= 24 in.

PART-B       Area of inside frame=6×4=24 square inches.

2)  

2 in.×32 in.4 in.×16 in.

4)  Dimensions of outside frame= 12.5 ft×17.5 ft.

Step-by-step explanation:

1)

PART-A

the outside frame has the measures as: 7 in. and 5 in.

i.e. the frame is in shape of a rectangle.

Perimeter of the outside edge= 7+7+5+5=14+10=24 in.

Hence, Perimeter= 24 in.

PART-B

Now we are asked to find the area of the inside of a frame as the frame is in the shape of a rectangle.

We know that the area of rectangle= l×b

where l represents the length of the frame and b represents the breadth of the rectangle.

Here we have l=6 in.

and b=4 in.

Hence,  Area of inside frame=6×4=24 square inches.

2)

Now we are given that the area of the frame was 64 inches².

So the possible dimensions could be:

2 in.×32 in.4 in.×16 in.

4)

Now we are using a scale factor as:

1 in.=2.5 ft.

the dimension of the outside frame was: 5 in.×7 in.

As 1 in.=2.5 ft.

5 in.=5×2.5=12.5 ft.

and 7 in.=7×2.5=17.5 ft.

Hence, the new dimension after using the scale factor is:

12.5 ft×17.5 ft.

Answer: question no. 1 -a. yes, the sides are in the ratio 2 : 5.question no. 2 -b. 59°question no. 3 -c. angles x and y are remote interior angles.question no. 4 -d. 90°, 45° and 45°question no. 5 -b. mn and qrstep-by-step explanation: question no. 1 -rs : xu = 3 : 7.5 = 2 : 5rt : x? = 6.4 : 16 = 2 : 5st : u? = 6 : 15 = 2 : 5as the ratios of all sides are equivalent, the triangles must be congruent and the sides must be proportional.therefore, the answer is: a. yes, the sides are in the ratio 2 : 5.question no. 2 -in the second diagram, angle b is the only letter not shown. therefore, the number must be equivalent to angle b.if we substitute the value of angle b as being 22° in the first diagram, we can now use the angle sum of a triangle to obtain the value of angle a.angle sum of a triangle = 180°therefore: let angle a = aa + 99 + 22 = 180a = 180 - 99 - 22a = 59°therefore, the answer is: b. 59°question no. 3 -angles x and y don't share the vertex of the triangle with the exterior angle w. remote interior angles don't share a vertex of a triangle with an exterior angle. this means that angles x and y are remote interior angles.therefore, the answer is: c. angles x and y are remote interior angles.question no. 4 -the sum of all interior angles of a triangle must be equivalent to 180°.90°, 45° and 45° are the only set of angle measures that are equivalent to 180°.therefore, the answer is: d. 90°, 45° and 45°question no. 5 -the only pair of sides stated in the options which are corresponding are mn and qr.therefore, the answer is: b. mn and qr.