Need asap a discount book store sells hardcover books for $8 each and paperbacks for $4 each. the number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day. the total amount of sales for that day was $160. jean-paul wrote the following system of linear equations to find the number of each type of book sold. 8h+4p=160 p4h+2 what was paul's error

Translate every statement into algebraic language.

1) hardcover books for $8 each

- name h the number of hardcover books
- amount of sale from hardcover books = 8h

2) paperbacks for $4 each

- namel p the number from paperback books
- amount of sale of paperbacks = 4p

3) the number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day.

-  h = 2 + 4p

4) the total amount of sales for that day was $160.

- 8h + 4p = 160

6) system of equations

h = 2 + 4p
8h + 4p = 160

5) Jean-Paul wrote the following system of linear equations to find the number of each type of book sold,

8H+4P=160
P=4H+2 < here is the error. This means that number of paperback books sold was 2 more than four times the number of hardcover books sold, when the right statement is that the number of hardcover book sold was 2 more than four times the number of paperback books, p, sold.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.