Looking for the solution for the pic below.

A' - C = {6, 8, 10, 11, 14}

Explanation:

The roster form of a set is the elements listed inside brackets { }.

And A' is the complement of A, this is the elements that are not in A.

Then, the roster form of the set A is { 1, 2, 3, 4, 5, 13}

The roster form of the set A' is {6, 7, 8, 9, 10, 11, 12, 14}.

The roster form of the set C: {1, 2, 7, 9, 12, 13}

The question is A' - C so it is the elements in the set A' less those elements that are also in C. So, you have to subract the elements 7, 9 and 12 from A'

The result is A' - C = {6, 8, 10, 11, 14}

The roster form of the set C is {1, 2, 7, 9, 12, 13}